3.1.37 \(\int (d x)^m (A+B x+C x^2) (a+b x^2+c x^4)^3 \, dx\) [37]

3.1.37.1 Optimal result
3.1.37.2 Mathematica [A] (verified)
3.1.37.3 Rubi [A] (verified)
3.1.37.4 Maple [B] (verified)
3.1.37.5 Fricas [B] (verification not implemented)
3.1.37.6 Sympy [B] (verification not implemented)
3.1.37.7 Maxima [A] (verification not implemented)
3.1.37.8 Giac [B] (verification not implemented)
3.1.37.9 Mupad [B] (verification not implemented)

3.1.37.1 Optimal result

Integrand size = 30, antiderivative size = 399 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\frac {a^3 A (d x)^{1+m}}{d (1+m)}+\frac {a^3 B (d x)^{2+m}}{d^2 (2+m)}+\frac {a^2 (3 A b+a C) (d x)^{3+m}}{d^3 (3+m)}+\frac {3 a^2 b B (d x)^{4+m}}{d^4 (4+m)}+\frac {3 a \left (A \left (b^2+a c\right )+a b C\right ) (d x)^{5+m}}{d^5 (5+m)}+\frac {3 a B \left (b^2+a c\right ) (d x)^{6+m}}{d^6 (6+m)}+\frac {\left (A \left (b^3+6 a b c\right )+3 a \left (b^2+a c\right ) C\right ) (d x)^{7+m}}{d^7 (7+m)}+\frac {b B \left (b^2+6 a c\right ) (d x)^{8+m}}{d^8 (8+m)}+\frac {\left (3 A c \left (b^2+a c\right )+b \left (b^2+6 a c\right ) C\right ) (d x)^{9+m}}{d^9 (9+m)}+\frac {3 B c \left (b^2+a c\right ) (d x)^{10+m}}{d^{10} (10+m)}+\frac {3 c \left (A b c+\left (b^2+a c\right ) C\right ) (d x)^{11+m}}{d^{11} (11+m)}+\frac {3 b B c^2 (d x)^{12+m}}{d^{12} (12+m)}+\frac {c^2 (A c+3 b C) (d x)^{13+m}}{d^{13} (13+m)}+\frac {B c^3 (d x)^{14+m}}{d^{14} (14+m)}+\frac {c^3 C (d x)^{15+m}}{d^{15} (15+m)} \]

output
a^3*A*(d*x)^(1+m)/d/(1+m)+a^3*B*(d*x)^(2+m)/d^2/(2+m)+a^2*(3*A*b+C*a)*(d*x 
)^(3+m)/d^3/(3+m)+3*a^2*b*B*(d*x)^(4+m)/d^4/(4+m)+3*a*(A*(a*c+b^2)+a*b*C)* 
(d*x)^(5+m)/d^5/(5+m)+3*a*B*(a*c+b^2)*(d*x)^(6+m)/d^6/(6+m)+(A*(6*a*b*c+b^ 
3)+3*a*(a*c+b^2)*C)*(d*x)^(7+m)/d^7/(7+m)+b*B*(6*a*c+b^2)*(d*x)^(8+m)/d^8/ 
(8+m)+(3*A*c*(a*c+b^2)+b*(6*a*c+b^2)*C)*(d*x)^(9+m)/d^9/(9+m)+3*B*c*(a*c+b 
^2)*(d*x)^(10+m)/d^10/(10+m)+3*c*(A*b*c+(a*c+b^2)*C)*(d*x)^(11+m)/d^11/(11 
+m)+3*b*B*c^2*(d*x)^(12+m)/d^12/(12+m)+c^2*(A*c+3*C*b)*(d*x)^(13+m)/d^13/( 
13+m)+B*c^3*(d*x)^(14+m)/d^14/(14+m)+c^3*C*(d*x)^(15+m)/d^15/(15+m)
 
3.1.37.2 Mathematica [A] (verified)

Time = 2.10 (sec) , antiderivative size = 296, normalized size of antiderivative = 0.74 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=x (d x)^m \left (\frac {a^3 A}{1+m}+\frac {a^3 B x}{2+m}+\frac {a^2 (3 A b+a C) x^2}{3+m}+\frac {3 a^2 b B x^3}{4+m}+\frac {3 a \left (A \left (b^2+a c\right )+a b C\right ) x^4}{5+m}+\frac {3 a B \left (b^2+a c\right ) x^5}{6+m}+\frac {\left (A \left (b^3+6 a b c\right )+3 a \left (b^2+a c\right ) C\right ) x^6}{7+m}+\frac {b B \left (b^2+6 a c\right ) x^7}{8+m}+\frac {\left (3 A c \left (b^2+a c\right )+b \left (b^2+6 a c\right ) C\right ) x^8}{9+m}+\frac {3 B c \left (b^2+a c\right ) x^9}{10+m}+\frac {3 c \left (A b c+\left (b^2+a c\right ) C\right ) x^{10}}{11+m}+\frac {3 b B c^2 x^{11}}{12+m}+\frac {c^2 (A c+3 b C) x^{12}}{13+m}+\frac {B c^3 x^{13}}{14+m}+\frac {c^3 C x^{14}}{15+m}\right ) \]

input
Integrate[(d*x)^m*(A + B*x + C*x^2)*(a + b*x^2 + c*x^4)^3,x]
 
output
x*(d*x)^m*((a^3*A)/(1 + m) + (a^3*B*x)/(2 + m) + (a^2*(3*A*b + a*C)*x^2)/( 
3 + m) + (3*a^2*b*B*x^3)/(4 + m) + (3*a*(A*(b^2 + a*c) + a*b*C)*x^4)/(5 + 
m) + (3*a*B*(b^2 + a*c)*x^5)/(6 + m) + ((A*(b^3 + 6*a*b*c) + 3*a*(b^2 + a* 
c)*C)*x^6)/(7 + m) + (b*B*(b^2 + 6*a*c)*x^7)/(8 + m) + ((3*A*c*(b^2 + a*c) 
 + b*(b^2 + 6*a*c)*C)*x^8)/(9 + m) + (3*B*c*(b^2 + a*c)*x^9)/(10 + m) + (3 
*c*(A*b*c + (b^2 + a*c)*C)*x^10)/(11 + m) + (3*b*B*c^2*x^11)/(12 + m) + (c 
^2*(A*c + 3*b*C)*x^12)/(13 + m) + (B*c^3*x^13)/(14 + m) + (c^3*C*x^14)/(15 
 + m))
 
3.1.37.3 Rubi [A] (verified)

Time = 0.76 (sec) , antiderivative size = 399, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {2159, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (d x)^m \left (a+b x^2+c x^4\right )^3 \left (A+B x+C x^2\right ) \, dx\)

\(\Big \downarrow \) 2159

\(\displaystyle \int \left (a^3 A (d x)^m+\frac {a^3 B (d x)^{m+1}}{d}+\frac {a^2 (d x)^{m+2} (a C+3 A b)}{d^2}+\frac {3 a^2 b B (d x)^{m+3}}{d^3}+\frac {3 c (d x)^{m+10} \left (C \left (a c+b^2\right )+A b c\right )}{d^{10}}+\frac {(d x)^{m+8} \left (3 A c \left (a c+b^2\right )+b C \left (6 a c+b^2\right )\right )}{d^8}+\frac {3 a (d x)^{m+4} \left (A \left (a c+b^2\right )+a b C\right )}{d^4}+\frac {(d x)^{m+6} \left (A \left (6 a b c+b^3\right )+3 a C \left (a c+b^2\right )\right )}{d^6}+\frac {3 B c \left (a c+b^2\right ) (d x)^{m+9}}{d^9}+\frac {b B \left (6 a c+b^2\right ) (d x)^{m+7}}{d^7}+\frac {3 a B \left (a c+b^2\right ) (d x)^{m+5}}{d^5}+\frac {c^2 (d x)^{m+12} (A c+3 b C)}{d^{12}}+\frac {3 b B c^2 (d x)^{m+11}}{d^{11}}+\frac {B c^3 (d x)^{m+13}}{d^{13}}+\frac {c^3 C (d x)^{m+14}}{d^{14}}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {a^3 A (d x)^{m+1}}{d (m+1)}+\frac {a^3 B (d x)^{m+2}}{d^2 (m+2)}+\frac {a^2 (d x)^{m+3} (a C+3 A b)}{d^3 (m+3)}+\frac {3 a^2 b B (d x)^{m+4}}{d^4 (m+4)}+\frac {3 c (d x)^{m+11} \left (C \left (a c+b^2\right )+A b c\right )}{d^{11} (m+11)}+\frac {(d x)^{m+9} \left (3 A c \left (a c+b^2\right )+b C \left (6 a c+b^2\right )\right )}{d^9 (m+9)}+\frac {3 a (d x)^{m+5} \left (A \left (a c+b^2\right )+a b C\right )}{d^5 (m+5)}+\frac {(d x)^{m+7} \left (A \left (6 a b c+b^3\right )+3 a C \left (a c+b^2\right )\right )}{d^7 (m+7)}+\frac {3 B c \left (a c+b^2\right ) (d x)^{m+10}}{d^{10} (m+10)}+\frac {b B \left (6 a c+b^2\right ) (d x)^{m+8}}{d^8 (m+8)}+\frac {3 a B \left (a c+b^2\right ) (d x)^{m+6}}{d^6 (m+6)}+\frac {c^2 (d x)^{m+13} (A c+3 b C)}{d^{13} (m+13)}+\frac {3 b B c^2 (d x)^{m+12}}{d^{12} (m+12)}+\frac {B c^3 (d x)^{m+14}}{d^{14} (m+14)}+\frac {c^3 C (d x)^{m+15}}{d^{15} (m+15)}\)

input
Int[(d*x)^m*(A + B*x + C*x^2)*(a + b*x^2 + c*x^4)^3,x]
 
output
(a^3*A*(d*x)^(1 + m))/(d*(1 + m)) + (a^3*B*(d*x)^(2 + m))/(d^2*(2 + m)) + 
(a^2*(3*A*b + a*C)*(d*x)^(3 + m))/(d^3*(3 + m)) + (3*a^2*b*B*(d*x)^(4 + m) 
)/(d^4*(4 + m)) + (3*a*(A*(b^2 + a*c) + a*b*C)*(d*x)^(5 + m))/(d^5*(5 + m) 
) + (3*a*B*(b^2 + a*c)*(d*x)^(6 + m))/(d^6*(6 + m)) + ((A*(b^3 + 6*a*b*c) 
+ 3*a*(b^2 + a*c)*C)*(d*x)^(7 + m))/(d^7*(7 + m)) + (b*B*(b^2 + 6*a*c)*(d* 
x)^(8 + m))/(d^8*(8 + m)) + ((3*A*c*(b^2 + a*c) + b*(b^2 + 6*a*c)*C)*(d*x) 
^(9 + m))/(d^9*(9 + m)) + (3*B*c*(b^2 + a*c)*(d*x)^(10 + m))/(d^10*(10 + m 
)) + (3*c*(A*b*c + (b^2 + a*c)*C)*(d*x)^(11 + m))/(d^11*(11 + m)) + (3*b*B 
*c^2*(d*x)^(12 + m))/(d^12*(12 + m)) + (c^2*(A*c + 3*b*C)*(d*x)^(13 + m))/ 
(d^13*(13 + m)) + (B*c^3*(d*x)^(14 + m))/(d^14*(14 + m)) + (c^3*C*(d*x)^(1 
5 + m))/(d^15*(15 + m))
 

3.1.37.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2159
Int[(Pq_)*((d_.) + (e_.)*(x_))^(m_.)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p 
_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*Pq*(a + b*x + c*x^2)^p, x 
], x] /; FreeQ[{a, b, c, d, e, m}, x] && PolyQ[Pq, x] && IGtQ[p, -2]
 
3.1.37.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(5519\) vs. \(2(399)=798\).

Time = 0.41 (sec) , antiderivative size = 5520, normalized size of antiderivative = 13.83

method result size
gosper \(\text {Expression too large to display}\) \(5520\)
risch \(\text {Expression too large to display}\) \(5520\)
parallelrisch \(\text {Expression too large to display}\) \(7809\)

input
int((d*x)^m*(C*x^2+B*x+A)*(c*x^4+b*x^2+a)^3,x,method=_RETURNVERBOSE)
 
output
result too large to display
 
3.1.37.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 3898 vs. \(2 (399) = 798\).

Time = 0.38 (sec) , antiderivative size = 3898, normalized size of antiderivative = 9.77 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\text {Too large to display} \]

input
integrate((d*x)^m*(C*x^2+B*x+A)*(c*x^4+b*x^2+a)^3,x, algorithm="fricas")
 
output
((C*c^3*m^14 + 105*C*c^3*m^13 + 5005*C*c^3*m^12 + 143325*C*c^3*m^11 + 2749 
747*C*c^3*m^10 + 37312275*C*c^3*m^9 + 368411615*C*c^3*m^8 + 2681453775*C*c 
^3*m^7 + 14409322928*C*c^3*m^6 + 56663366760*C*c^3*m^5 + 159721605680*C*c^ 
3*m^4 + 310989260400*C*c^3*m^3 + 392156797824*C*c^3*m^2 + 283465647360*C*c 
^3*m + 87178291200*C*c^3)*x^15 + (B*c^3*m^14 + 106*B*c^3*m^13 + 5096*B*c^3 
*m^12 + 147056*B*c^3*m^11 + 2840838*B*c^3*m^10 + 38786748*B*c^3*m^9 + 3850 
81268*B*c^3*m^8 + 2816490248*B*c^3*m^7 + 15200266081*B*c^3*m^6 + 599994855 
46*B*c^3*m^5 + 169679309436*B*c^3*m^4 + 331303013496*B*c^3*m^3 + 418753514 
880*B*c^3*m^2 + 303268406400*B*c^3*m + 93405312000*B*c^3)*x^14 + ((3*C*b*c 
^2 + A*c^3)*m^14 + 107*(3*C*b*c^2 + A*c^3)*m^13 + 5189*(3*C*b*c^2 + A*c^3) 
*m^12 + 150943*(3*C*b*c^2 + A*c^3)*m^11 + 2937363*(3*C*b*c^2 + A*c^3)*m^10 
 + 40372761*(3*C*b*c^2 + A*c^3)*m^9 + 403249847*(3*C*b*c^2 + A*c^3)*m^8 + 
2965379989*(3*C*b*c^2 + A*c^3)*m^7 + 16081189696*(3*C*b*c^2 + A*c^3)*m^6 + 
 63747744632*(3*C*b*c^2 + A*c^3)*m^5 + 180951426864*(3*C*b*c^2 + A*c^3)*m^ 
4 + 301771008000*C*b*c^2 + 100590336000*A*c^3 + 354444796368*(3*C*b*c^2 + 
A*c^3)*m^3 + 449213351040*(3*C*b*c^2 + A*c^3)*m^2 + 326044051200*(3*C*b*c^ 
2 + A*c^3)*m)*x^13 + 3*(B*b*c^2*m^14 + 108*B*b*c^2*m^13 + 5284*B*b*c^2*m^1 
2 + 154992*B*b*c^2*m^11 + 3039718*B*b*c^2*m^10 + 42081864*B*b*c^2*m^9 + 42 
3113372*B*b*c^2*m^8 + 3130267536*B*b*c^2*m^7 + 17067919121*B*b*c^2*m^6 + 6 
7988181228*B*b*c^2*m^5 + 193813932344*B*b*c^2*m^4 + 381046157472*B*b*c^...
 
3.1.37.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 47658 vs. \(2 (379) = 758\).

Time = 3.03 (sec) , antiderivative size = 47658, normalized size of antiderivative = 119.44 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\text {Too large to display} \]

input
integrate((d*x)**m*(C*x**2+B*x+A)*(c*x**4+b*x**2+a)**3,x)
 
output
Piecewise(((-A*a**3/(14*x**14) - A*a**2*b/(4*x**12) - 3*A*a**2*c/(10*x**10 
) - 3*A*a*b**2/(10*x**10) - 3*A*a*b*c/(4*x**8) - A*a*c**2/(2*x**6) - A*b** 
3/(8*x**8) - A*b**2*c/(2*x**6) - 3*A*b*c**2/(4*x**4) - A*c**3/(2*x**2) - B 
*a**3/(13*x**13) - 3*B*a**2*b/(11*x**11) - B*a**2*c/(3*x**9) - B*a*b**2/(3 
*x**9) - 6*B*a*b*c/(7*x**7) - 3*B*a*c**2/(5*x**5) - B*b**3/(7*x**7) - 3*B* 
b**2*c/(5*x**5) - B*b*c**2/x**3 - B*c**3/x - C*a**3/(12*x**12) - 3*C*a**2* 
b/(10*x**10) - 3*C*a**2*c/(8*x**8) - 3*C*a*b**2/(8*x**8) - C*a*b*c/x**6 - 
3*C*a*c**2/(4*x**4) - C*b**3/(6*x**6) - 3*C*b**2*c/(4*x**4) - 3*C*b*c**2/( 
2*x**2) + C*c**3*log(x))/d**15, Eq(m, -15)), ((-A*a**3/(13*x**13) - 3*A*a* 
*2*b/(11*x**11) - A*a**2*c/(3*x**9) - A*a*b**2/(3*x**9) - 6*A*a*b*c/(7*x** 
7) - 3*A*a*c**2/(5*x**5) - A*b**3/(7*x**7) - 3*A*b**2*c/(5*x**5) - A*b*c** 
2/x**3 - A*c**3/x - B*a**3/(12*x**12) - 3*B*a**2*b/(10*x**10) - 3*B*a**2*c 
/(8*x**8) - 3*B*a*b**2/(8*x**8) - B*a*b*c/x**6 - 3*B*a*c**2/(4*x**4) - B*b 
**3/(6*x**6) - 3*B*b**2*c/(4*x**4) - 3*B*b*c**2/(2*x**2) + B*c**3*log(x) - 
 C*a**3/(11*x**11) - C*a**2*b/(3*x**9) - 3*C*a**2*c/(7*x**7) - 3*C*a*b**2/ 
(7*x**7) - 6*C*a*b*c/(5*x**5) - C*a*c**2/x**3 - C*b**3/(5*x**5) - C*b**2*c 
/x**3 - 3*C*b*c**2/x + C*c**3*x)/d**14, Eq(m, -14)), ((-A*a**3/(12*x**12) 
- 3*A*a**2*b/(10*x**10) - 3*A*a**2*c/(8*x**8) - 3*A*a*b**2/(8*x**8) - A*a* 
b*c/x**6 - 3*A*a*c**2/(4*x**4) - A*b**3/(6*x**6) - 3*A*b**2*c/(4*x**4) - 3 
*A*b*c**2/(2*x**2) + A*c**3*log(x) - B*a**3/(11*x**11) - B*a**2*b/(3*x*...
 
3.1.37.7 Maxima [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 611, normalized size of antiderivative = 1.53 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\frac {C c^{3} d^{m} x^{15} x^{m}}{m + 15} + \frac {B c^{3} d^{m} x^{14} x^{m}}{m + 14} + \frac {3 \, C b c^{2} d^{m} x^{13} x^{m}}{m + 13} + \frac {A c^{3} d^{m} x^{13} x^{m}}{m + 13} + \frac {3 \, B b c^{2} d^{m} x^{12} x^{m}}{m + 12} + \frac {3 \, C b^{2} c d^{m} x^{11} x^{m}}{m + 11} + \frac {3 \, C a c^{2} d^{m} x^{11} x^{m}}{m + 11} + \frac {3 \, A b c^{2} d^{m} x^{11} x^{m}}{m + 11} + \frac {3 \, B b^{2} c d^{m} x^{10} x^{m}}{m + 10} + \frac {3 \, B a c^{2} d^{m} x^{10} x^{m}}{m + 10} + \frac {C b^{3} d^{m} x^{9} x^{m}}{m + 9} + \frac {6 \, C a b c d^{m} x^{9} x^{m}}{m + 9} + \frac {3 \, A b^{2} c d^{m} x^{9} x^{m}}{m + 9} + \frac {3 \, A a c^{2} d^{m} x^{9} x^{m}}{m + 9} + \frac {B b^{3} d^{m} x^{8} x^{m}}{m + 8} + \frac {6 \, B a b c d^{m} x^{8} x^{m}}{m + 8} + \frac {3 \, C a b^{2} d^{m} x^{7} x^{m}}{m + 7} + \frac {A b^{3} d^{m} x^{7} x^{m}}{m + 7} + \frac {3 \, C a^{2} c d^{m} x^{7} x^{m}}{m + 7} + \frac {6 \, A a b c d^{m} x^{7} x^{m}}{m + 7} + \frac {3 \, B a b^{2} d^{m} x^{6} x^{m}}{m + 6} + \frac {3 \, B a^{2} c d^{m} x^{6} x^{m}}{m + 6} + \frac {3 \, C a^{2} b d^{m} x^{5} x^{m}}{m + 5} + \frac {3 \, A a b^{2} d^{m} x^{5} x^{m}}{m + 5} + \frac {3 \, A a^{2} c d^{m} x^{5} x^{m}}{m + 5} + \frac {3 \, B a^{2} b d^{m} x^{4} x^{m}}{m + 4} + \frac {C a^{3} d^{m} x^{3} x^{m}}{m + 3} + \frac {3 \, A a^{2} b d^{m} x^{3} x^{m}}{m + 3} + \frac {B a^{3} d^{m} x^{2} x^{m}}{m + 2} + \frac {\left (d x\right )^{m + 1} A a^{3}}{d {\left (m + 1\right )}} \]

input
integrate((d*x)^m*(C*x^2+B*x+A)*(c*x^4+b*x^2+a)^3,x, algorithm="maxima")
 
output
C*c^3*d^m*x^15*x^m/(m + 15) + B*c^3*d^m*x^14*x^m/(m + 14) + 3*C*b*c^2*d^m* 
x^13*x^m/(m + 13) + A*c^3*d^m*x^13*x^m/(m + 13) + 3*B*b*c^2*d^m*x^12*x^m/( 
m + 12) + 3*C*b^2*c*d^m*x^11*x^m/(m + 11) + 3*C*a*c^2*d^m*x^11*x^m/(m + 11 
) + 3*A*b*c^2*d^m*x^11*x^m/(m + 11) + 3*B*b^2*c*d^m*x^10*x^m/(m + 10) + 3* 
B*a*c^2*d^m*x^10*x^m/(m + 10) + C*b^3*d^m*x^9*x^m/(m + 9) + 6*C*a*b*c*d^m* 
x^9*x^m/(m + 9) + 3*A*b^2*c*d^m*x^9*x^m/(m + 9) + 3*A*a*c^2*d^m*x^9*x^m/(m 
 + 9) + B*b^3*d^m*x^8*x^m/(m + 8) + 6*B*a*b*c*d^m*x^8*x^m/(m + 8) + 3*C*a* 
b^2*d^m*x^7*x^m/(m + 7) + A*b^3*d^m*x^7*x^m/(m + 7) + 3*C*a^2*c*d^m*x^7*x^ 
m/(m + 7) + 6*A*a*b*c*d^m*x^7*x^m/(m + 7) + 3*B*a*b^2*d^m*x^6*x^m/(m + 6) 
+ 3*B*a^2*c*d^m*x^6*x^m/(m + 6) + 3*C*a^2*b*d^m*x^5*x^m/(m + 5) + 3*A*a*b^ 
2*d^m*x^5*x^m/(m + 5) + 3*A*a^2*c*d^m*x^5*x^m/(m + 5) + 3*B*a^2*b*d^m*x^4* 
x^m/(m + 4) + C*a^3*d^m*x^3*x^m/(m + 3) + 3*A*a^2*b*d^m*x^3*x^m/(m + 3) + 
B*a^3*d^m*x^2*x^m/(m + 2) + (d*x)^(m + 1)*A*a^3/(d*(m + 1))
 
3.1.37.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 7808 vs. \(2 (399) = 798\).

Time = 0.40 (sec) , antiderivative size = 7808, normalized size of antiderivative = 19.57 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\text {Too large to display} \]

input
integrate((d*x)^m*(C*x^2+B*x+A)*(c*x^4+b*x^2+a)^3,x, algorithm="giac")
 
output
((d*x)^m*C*c^3*m^14*x^15 + (d*x)^m*B*c^3*m^14*x^14 + 105*(d*x)^m*C*c^3*m^1 
3*x^15 + 3*(d*x)^m*C*b*c^2*m^14*x^13 + (d*x)^m*A*c^3*m^14*x^13 + 106*(d*x) 
^m*B*c^3*m^13*x^14 + 5005*(d*x)^m*C*c^3*m^12*x^15 + 3*(d*x)^m*B*b*c^2*m^14 
*x^12 + 321*(d*x)^m*C*b*c^2*m^13*x^13 + 107*(d*x)^m*A*c^3*m^13*x^13 + 5096 
*(d*x)^m*B*c^3*m^12*x^14 + 143325*(d*x)^m*C*c^3*m^11*x^15 + 3*(d*x)^m*C*b^ 
2*c*m^14*x^11 + 3*(d*x)^m*C*a*c^2*m^14*x^11 + 3*(d*x)^m*A*b*c^2*m^14*x^11 
+ 324*(d*x)^m*B*b*c^2*m^13*x^12 + 15567*(d*x)^m*C*b*c^2*m^12*x^13 + 5189*( 
d*x)^m*A*c^3*m^12*x^13 + 147056*(d*x)^m*B*c^3*m^11*x^14 + 2749747*(d*x)^m* 
C*c^3*m^10*x^15 + 3*(d*x)^m*B*b^2*c*m^14*x^10 + 3*(d*x)^m*B*a*c^2*m^14*x^1 
0 + 327*(d*x)^m*C*b^2*c*m^13*x^11 + 327*(d*x)^m*C*a*c^2*m^13*x^11 + 327*(d 
*x)^m*A*b*c^2*m^13*x^11 + 15852*(d*x)^m*B*b*c^2*m^12*x^12 + 452829*(d*x)^m 
*C*b*c^2*m^11*x^13 + 150943*(d*x)^m*A*c^3*m^11*x^13 + 2840838*(d*x)^m*B*c^ 
3*m^10*x^14 + 37312275*(d*x)^m*C*c^3*m^9*x^15 + (d*x)^m*C*b^3*m^14*x^9 + 6 
*(d*x)^m*C*a*b*c*m^14*x^9 + 3*(d*x)^m*A*b^2*c*m^14*x^9 + 3*(d*x)^m*A*a*c^2 
*m^14*x^9 + 330*(d*x)^m*B*b^2*c*m^13*x^10 + 330*(d*x)^m*B*a*c^2*m^13*x^10 
+ 16143*(d*x)^m*C*b^2*c*m^12*x^11 + 16143*(d*x)^m*C*a*c^2*m^12*x^11 + 1614 
3*(d*x)^m*A*b*c^2*m^12*x^11 + 464976*(d*x)^m*B*b*c^2*m^11*x^12 + 8812089*( 
d*x)^m*C*b*c^2*m^10*x^13 + 2937363*(d*x)^m*A*c^3*m^10*x^13 + 38786748*(d*x 
)^m*B*c^3*m^9*x^14 + 368411615*(d*x)^m*C*c^3*m^8*x^15 + (d*x)^m*B*b^3*m^14 
*x^8 + 6*(d*x)^m*B*a*b*c*m^14*x^8 + 111*(d*x)^m*C*b^3*m^13*x^9 + 666*(d...
 
3.1.37.9 Mupad [B] (verification not implemented)

Time = 9.25 (sec) , antiderivative size = 2443, normalized size of antiderivative = 6.12 \[ \int (d x)^m \left (A+B x+C x^2\right ) \left (a+b x^2+c x^4\right )^3 \, dx=\text {Too large to display} \]

input
int((d*x)^m*(A + B*x + C*x^2)*(a + b*x^2 + c*x^4)^3,x)
 
output
(x^7*(d*x)^m*(A*b^3 + 3*C*a*b^2 + 3*C*a^2*c + 6*A*a*b*c)*(593193196800*m + 
 796089202560*m^2 + 608700928752*m^3 + 299730345264*m^4 + 101420251688*m^5 
 + 24483279856*m^6 + 4306835671*m^7 + 557256047*m^8 + 52977099*m^9 + 36544 
83*m^10 + 177877*m^11 + 5789*m^12 + 113*m^13 + m^14 + 186810624000))/(4339 
163001600*m + 6165817614720*m^2 + 5056995703824*m^3 + 2706813345600*m^4 + 
1009672107080*m^5 + 272803210680*m^6 + 54631129553*m^7 + 8207628000*m^8 + 
928095740*m^9 + 78558480*m^10 + 4899622*m^11 + 218400*m^12 + 6580*m^13 + 1 
20*m^14 + m^15 + 1307674368000) + (x^9*(d*x)^m*(C*b^3 + 3*A*a*c^2 + 3*A*b^ 
2*c + 6*C*a*b*c)*(465985094400*m + 633314724480*m^2 + 491520108816*m^3 + 2 
46143692976*m^4 + 84836490456*m^5 + 20885191136*m^6 + 3749548713*m^7 + 495 
342143*m^8 + 48083733*m^9 + 3386083*m^10 + 168171*m^11 + 5581*m^12 + 111*m 
^13 + m^14 + 145297152000))/(4339163001600*m + 6165817614720*m^2 + 5056995 
703824*m^3 + 2706813345600*m^4 + 1009672107080*m^5 + 272803210680*m^6 + 54 
631129553*m^7 + 8207628000*m^8 + 928095740*m^9 + 78558480*m^10 + 4899622*m 
^11 + 218400*m^12 + 6580*m^13 + 120*m^14 + m^15 + 1307674368000) + (B*c^3* 
x^14*(d*x)^m*(303268406400*m + 418753514880*m^2 + 331303013496*m^3 + 16967 
9309436*m^4 + 59999485546*m^5 + 15200266081*m^6 + 2816490248*m^7 + 3850812 
68*m^8 + 38786748*m^9 + 2840838*m^10 + 147056*m^11 + 5096*m^12 + 106*m^13 
+ m^14 + 93405312000))/(4339163001600*m + 6165817614720*m^2 + 505699570382 
4*m^3 + 2706813345600*m^4 + 1009672107080*m^5 + 272803210680*m^6 + 5463...